Re: x^y<0
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29 Apr 2023, 00:23
Given that \(𝑥^𝑦 < 0\), this implies that
QA Though there are certain restrictions on the possible values of 𝑦 , for the expression \(𝑥^𝑦\) to be negative, base 𝑥 should be negative. Hence, Quantity A is negative.
QB We can observe that for \(𝑥^𝑦\) to be negative 𝑦 cannot be even. However, it can be odd or in certain cases a fraction, (as even power always gives nonnegative answer), but nothing about the sign of 𝑦 can be concluded. Hence, Quantity B can be positive or negative.
D is the answer. Very tricky question to solve rather conceptually
I suggest you to follow the link at the bottom of the question above >>> Inequalities theory